If the terminal ray of β lies in the third quadrant and the value of sin(β) is shown below. Determine cos(β) in the simplest form. Please show your calculations that lead to your answer. sin(B)=-√3/3

Step-by-step explanation:

It is given that lies in the third quadrant.

In 3rd quadrant, sine and cosine both are negative.

Also given that:

We know that identity between sine and cosine as:

Here,

Therefore, the identity can be written as:

Putting the value of :

But, it is given that is in 3rd quadrant. That means, value of cos will be negative.

Therefore, the correct answer is:

idk

step-by-step explanation:

use that smart brain

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation: