Given that Ray E B bisects ∠CEA, which statements must be true? Select three options. m∠CEA = 90° m∠CEF = m∠CEA + m∠BEF m∠CEB = 2(m∠CEA) ∠CEF is a straight angle. ∠AEF is a right angle.

The three statements that must be true are:

m∠CEA = 90°

∠CEF is a straight angle

∠AEF is a right angle.

Let's analyze each of the given options using the information given to us and determine whether they are true or not:

The small rectangular sign-shape included in the diagram is used to indicate that a right angle which is 90°.

Therefore, the statement, "m∠CEA = 90°" is TRUE.

This is FALSE.

m<CEF = m<CEA + AEF NOT m∠CEF = m∠CEA + m∠BEF.

This is also FALSE because,

m<CEB is half of m<CEA since ray EB bisects <CEA.

This is TRUE, because,

m<CEF = m<CEA + m<AEF = 180° (straight line angle = 180°)

This is also TRUE because,

m<AEF = 90°

A right angle = 90°

m∠CEA = 90°

∠CEF is a straight angle

∠AEF is a right angle.

Learn more about angles here:

link

mCEA = 90ᴼ because CEA is a right angle, and right angles have 90ᴼ measures.

CEF is a straight angle because there are two 90ᴼ angles (CEA and AEF) and therefore there is 180ᴼ in total. A straight line has a measure of 180ᴼ.

AEF is a right angle because if CEA is a right angle and CEF is a straight line, then AEF has to be a right angle.

answer: x

step-by-step explanation: