Complete the following proof. Given: Points R, S, T, Q on circle O Prove: m\overarc RS + m\overarc ST + m\overarc TQ + m\overarc RQ

360°

Step-by-step explanation:

From the figure attached,

R, S, T and Q are the points on a circle O.

Since, "measure of an arc of a circle is equal to the measure of the angle subtended by the arc at the center."

By this statement,

m(major arc RQ) = m(∠QOR)

Now + m(major arc RQ) =

Since sum of all angles at a point = 360°

+ m(major arc RQ) = 360°

answer: im gonna go with milli

step-by-step explanation:

im not sure of the names, but the answer is 48