How many units long is a segment whose endpoints are (-4,1) and (1,13)?

13

Step-by-step explanation:

(1−−4)2+(13−1)2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√(1++0)2+(13−1)2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√(5)2+(12)2‾‾‾‾‾‾‾‾‾‾‾√25+144‾‾‾‾‾‾‾‾‾√169‾‾‾‾√≈13

Sorry if the explanation is a bit confusing but, I used the distance formula to do this.

Hope this helps

D = 13

Step-by-step explanation:

We'll find its length using Distance Formula:

Distance Formula =

D =

D =

D =

D =

D = 13

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

the first one, all those points on the line just make a strait line.