Eve is organizing a race to raise money for a local children's hospital. She makes $20 for each 5K participant and $45 for each 10K participant. Her goal is to raise $9,500. If x represents the number of participants in the 5K race and y represents the number of participants in the 10K race, the linear equation for the given scenario is x + y = .

225

Step-by-step explanation:

(9000/45) + (500/20) =200 + 25 = 225

x=25, y=200

Step-by-step explanation:

It is given that x is the number of participants in the 5K race and y is the number of participants in the 10K race.

20x+45y=9500

Eve makes $20 for each 5K participant and $45 for each 10K participant. She wants to raise $9,500. The linear equation below represents the given scenario.

20x+45y=9500

20(200+45y=9500

4400+45y=9500

45y=9500

y ==113.3 (curvy equal sign)

If Eve raises exactly $9,500 and there are 220 5K participants, the number of 10K participants is found as shown below.

It is not possible to have 113.3 participants in the 10K race. So, no, it is not possible for Eve to raise exactly $9,500 if there are 220 participants in the 5K race.

i wish i could u

step-by-step explanation:

i wish i could u

stops on an even number.