The sample space listing the eight simple events that are possible when a couple has three children is {bbb, bbg, bgb, bgg, gbb, gbg, ggb, ggg}. After identifying the sample space for a couple having four children, find the probability of getting two girls and two boys (in any order).Identify the sample space for a couple having four children. Find the probability of getting two Girls and two boys (in any order).2.Multiple-choice questions each havefourpossible answers (a, b, c, d),one of which is correct. Assume that you guess the answers to three such questions. a. Use the multiplication rule to findP(CWW),where C denotes a correct answer and W denotes a wrong answer. P(CWW)equals=(Type an exact answer.)In a study of helicopter usage and patient survival, among the 48,693 patients transported by helicopter,280 of them left the treatment center against medical advice, and the other 48,413 did not leave against medical advice. If 60 of the subjects transported by helicopter are randomly selected without replacement, what is the probability that none of them left the treatment center against medical advice?The probability isFind the probability that when a couple has three children, at least one of them is a girl.(Assume that boys and girls are equallylikely.)The probability isthat at least one of the three children is a girl. Refer to the accompanyingtable, which describes results from groups of 8 births from 8 different sets of parents. The random variable x represents the number of girls among 8 children. Find the mean and standard deviation for the number of girls in 8 births. Number ofGirls xP(x)00.0031 0.0282 0.1023 0.2154 0.3005 0.2116 0.1057 0.0338 0.003The mean is μ equals=4.0girl(s). (Round to one decimal place as needed.)The standard deviation is σ equals=nothinggirl(s). (Round to one decimal place as needed.)