Find x please help thank you A. 33–√ B. 32√2 C. 3 D. 6–√

Step-by-step explanation:

You know the short side of an isosceles right triangle is 1/√2 times the hypotenuse. So, the hypotenuse of the 30°-60°-90° right triangle is ...

  6/√2 = (6√2)/2 = 3√2

You also know the short leg of a 30°-60°-90° right triangle is half the length of its hypotenuse, so ...

  x = (1/2)(3√2)

  x = (3/2)√2

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Additional comment

For many trig and geometry problems, it is useful to remember the ratios of side lengths for "special" right triangles:

  isosceles right triangle: 1 : 1 : √2

  30°-60°-90° triangle: 1 : √3 : 2     (shortest to longest)

This knowledge usefully relates to the trig function values for these "special" triangles.

3/√2 or 3√2/2

Step-by-step explanation:

Bigger triangle has internal angles 45/45/90, so the legs have equal length and = 6/√2 as hypotenuse = 6

Smaller triangle has hypotenuse of 6/√2 and the angle against leg x is 30°

As we know the leg opposite to 30° angle is half the hypotenuse, so

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

1/4 is the answer if i recall correctly.