Solve on the interval [0, 2pi):
1 + cos(theta) = (sqrt(3)+2)/2
a. pi/6 , 5pi/6
b. pi/3 , 5pi/3
c. pi/6 , 11pi/6
d. 7pi/6, 11pi/6

Option C is right

Step-by-step explanation:

Now we cancel 1 and get

The solutions would be positive for cos hence the angle lies in I quadrant, IV quadrant.

In I quadrant angle satisfying in the I quadrant, is 30 degrees, pi/6

In IV quadrant this would be 2pi-pi/6 = 11pi/6

Hence solution is

pi/6, 11 pi/6

OPtionC

the circle graph is not a function.

step-by-step explanation:

the graph of the circle is not a function.

because for a graph to be a function, each value of x must give one value of y

in the circle, the values of x for -2< x< 2 each give 2 values of y.

hence this is not a function.

7

step-by-step explanation: