NEED IT DONE ASAP. Find three consecutive numbers such that the sum of one-third the first and one-fifth the second is three more than one-half the third. 110, 111, 112 114, 115, 116 120, 121, 121

111, 116, 120

Step-by-step explanation:

111 ÷ 3 = (37)

120 ÷ 5 = (24)

24 + 37 = 61

116 ÷ 2 = 58

61 - 58 = 3

therefore 61 is 3 more than 61

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )

y = i/2 xtnop + (3i/2 tnop+ 1)

step-by-step explanation:

the picture is the step by step explanation.