Two bond funds pay interest at rates that differ by 4%. Money invested for one year in the first fund earns $550 interest. The same amount invested in the other fund earns $770. Find the lower rate of interest. %

10% interest.

Step-by-step explanation:

Interest I = PRT/100

If the rate R = x% we have

550 = P*x *1 / 100

and

770 = P*(x + 4) * 1 / 100

so From  first equation

Px = 55000  and from the second

Px + 4P =  77000

So Px = 77000 - 4P

Therefore  77000 - 4P = 55000

4P = 22000

P = 5,500

So x = 55000/5500 = 10%.

And  the rate for the other fund is 10 + 4 = 14%.

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )

22 dimes and 9 nickels

step-by-step explanation: