Point M is in the interior of angle AOB, the ray OC is a bisector of this angle. Prove that the measure of angle MOC is equal to one-half the difference of the measure of angles AOM and BOM

Step-by-step explanation:

Given: point M,

           m<AOB,

           OC the bisector of m<AOB

Thus,

m<AOC = m<BOC (bisector property of OC)

m<MOC = m<BOM (congruence property)

m<AOM - m<BOM = m<AOC = m<BOC

m<BOC = m<MOC =  (angle property)

Therefore,

m<AOM > m<BOM (point M location property)

m<MOC =

y = 2x

step-by-step explanation:

if you divide each number in the sequence, you'll see that they all have a multiple factor of 2. each number in the series, and any other numbers which may continue, will be multiplied by 2. therefore, y is the next number in the sequence, and x is the current one, so, our formula will be y = 2x.

5050 i think

step-by-step explanation: