Point M is in the exterior of an angle AOB, ray OC is a bisector of this angle. Prove, that the measure of angle MOC is equal to one-half the sum of the measures of angles AOM and BOM.

see the prove below

Step-by-step explanation:

We have to prove that MOC=(AOM+BOM)/2

Let Angle AOM=x and AOC=y .  => AOB=2y ( because OC is the bisector of AOB)

So MOC= AOM+AOC=x+y

BOM=AOB+AOM=2y +x

AOM+BOM= x+2y+x=2y+2x

(AOM+BOM)/2= (2y+2x)/2=x+y=MOC

The statement is proved

she played for 18.75 hours.

step-by-step explanation:

if she played 2/4 of a hour on tuesday. and there is 60 minutes in an hour and 60 divided by 4 is 7.5. and she played 2/4 of an hour on thursday then again 60 divided by 4 is 7.5, you add 7.5+7.5=56.25. now you have to do 1/4 of an hour, it equals 3.75. now you have to add them all up. 3.75+7.5+7.5=18.75

i hope this and i hope you get it right. it took me a while to get this done for you. : )

i would be happy to . most people on would also love to i'm sure. if you just want someone who has done algebra before and want a little more personal relationship than just begging strangers for , i can certainly be of service. i do have college myself so i might not be 24/7.