An object is launched directly in the air speed of 16 feet per second from a platform located 5 feet above the ground. The position of the object can be modeled using the function f(x)=-16t^2+16t+5, where t is the time of seconds and f(t) is the height of the object. What is the maximum height in feet that the object will reach?

The maximum height that the object will reach is of 9 feet.

Step-by-step explanation:

Vertex of a quadratic function:

Suppose we have a quadratic function in the following format:

It's vertex is the point

In which

If a<0, the vertex is a maximum point, that is, the maximum value happens at , and it's value is

In this question:

So

The instant of the maximum height is:

The maximum height is:

The maximum height that the object will reach is of 9 feet.

the answer to the question is a  

it has the same slope and the same y-intercept.

i'm not entirely sure

step-by-step explanation:

if you ask home depot or lowe's they might be able to you out