There are only red, blue and green counters in a bag. There are 6 red counters,4 blue counters and 8 green counters. Matt takes a counter from the bag at random a) What is the probability that the counter is red. Give your answer in a fraction. b) What is the probability that the counter is not blue. Give the answer as a fraction. pls help.

a) 1/3

b) 7/9

Step-by-step explanation:

The first part asks for the probability that Matt takes the red counter.

There are 6 red counters out of total 6+4+8 = 18 counters.

6/18

Simplify the fraction.

= 1/3

The second part asks for the probability that the counter is not blue.

The counters that are blue are 4. Not blue becomes 18-4 = 14. 14 red or green counters out of total 18.

14/18

= 7/9

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step-by-step explanation:

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step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)