Please assist me with this problem Given: Triangle ABC is a right triangle
Prove: a^2 + b^2 = c^2

Which is not a justification for the proof?

a. Pieces of Right Triangles Similarity Theorem

b. Side-Side-Side Similarity Theorem

c. Substitution

d. Addition Property of Equality

Option B is not a justification

Step-by-step explanation:

Option A is a justification (to get two pair of similar triangles (ABC-ACD) and (ABC-BCD))

Option C is a justification (a^2 = cy, b^2 = cx, a^2 + b^2 = cy + cx)

Option D is a justification (a^2 + b^2 = cy + cx = c(y + x) = c^2)

=> Option B is not a justification

b. an equilateral triangle inscribed in a circle

step-by-step explanation:

we are given the figure of two circles having a triangle inside.

now, we know that,

"when a figure is lying inside an another figure, then the outside figure is known as circumscribed figure and the figure lying inside is referred to as the inscribed figure".

as we see that, the circles are containing the triangle completely.

thus, the circles are the circumscribed figures and the triangle is the inscribed figure.

hence, we get, 'an equilateral triangle is inscribed in a circle'.

+25 = x

step-by-step explanation:

here x is the hypotenuse of a right triangle whose legs are 7 and 24.   by the pythagorean theorem, 7² + 24² must equal x²:

x² = 49 + 576 = 625.   thus, x = +√625 = +25 = x