Priscilla has three cups of apples left. She wants to use them in another fruit salad. How would she find out how much of the other fruits she needs to use up the
remaining apples?

To use up the remaining 3cups of apples, she would need 3cups of oranges, 12cups of strawberries, 6cups of cherry and 9 cups of grape.

Step-by-step explanation:

This is a continuation of the question on the recipe for making salad. The initial recipe from her grandmother is stated below (found on , ID 6786167).

The fruit salad recipe calls for one part apple, one part orange, four parts strawberry, two parts cherry, and three parts grape.

Priscilla uses the same measuring cup to measure all of the fruit, so one part is equal to one cup of diced fruit.

Number of cups required for each fruit in the original recipe:

apple = 1 cup , orange = 1 cup, strawberry = 4cups, cherry = 2cups, grape = 3cups

Original ratios of the cup of fruit respectively = 1:1:4:2:3

Total number of cups required in the original recipe: 1+1+4+2+3 = 11 cups

Now for this question, 3 cups of apples are remaining. And we want to find number of other fruits she needs in order to use up the remaining apples.

To do this we would use the ratios of the cup of fruit.

When we had 1 apple, the ratio was = 1

Now we have 3apples, the new ratio = 3×original ratio

=3×1 = 3

This means we would multiply each of the fruit ratios by 3

For orange, new ratio = 3×1 = 3

For strawberries, new ratio = 3×4 = 12

For cherry, new ratio = 3×2 = 6

For grape, new ratio = 3×3 = 9

To use up the remaining 3cups of apples, she would need 3cups of oranges, 12cups of strawberries, 6cups of cherry and 9 cups of grape.

36 is the final answer! : )

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.