A machine lifts up containers of coal from the mine and lowers empty containers down. The machine uses an electric motor connected to a 600 V d. c. supply. The maximum current in the motor is 4000 A. *Calculate the maximum power available from the motor. Give your answer in MW* power = voltage x current i believe

The maximum power available to the motor is 2.4 MW

Step-by-step explanation:

The power of  a circuit that has a current, I, and a voltage, V, is given by the relation

Electrical power, P = I²R = I× I×R = I × V

Therefore given that the parameters are;

Voltage in the d.c. power supply = 600 V d.c.

Maximum current in the motor = 4000 A

Therefore, we can find the power as follows;

Maximum motor power = Voltage × Current

The maximum motor power, P available =  600 V × 4000 A = 2400000 W which on converting to MW becomes;

The maximum power available to the motor , P = 2.4 MW.

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y=mx+b

step-by-step explanation:

m slope, b y-intercept