Determine the equation for the given line in slope-intercept form.
Oy=-5/3x-1
Oy= 5/3x+1
Oy= 3/5x+1
Oy=-3/5x+1

Equation of a line is y = mx + c

where m is the slope

c is the y intercept

From the graph using points ( 5 , - 4) and

( -5 , 2)

Slope = 2+4/ -5 - 5= 6/-10 = - 3/5

Equation of the line using point (5,-4) is

y + 4 = -3/5(x - 5)

y = -3/5x + 3 - 4

y = -3/5x - 1

Hope this helps

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)