A sample of 80 Valencia oranges showed a mean weight of 5.5 ounces with a standard deviation of 0.2 ounces. Obtain a 95% confidence interval for the weight of Valencia oranges. [5.495, 5.505 ] [0.195, 0.205] [ 5.456,5.544] [0.156, 0.244 )

[ 5.456, 5.544]

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean x = 5.5 ounces

Standard deviation r = 0.2 ounces

Number of samples n = 80

Confidence interval = 95%

z value (at 95% confidence) = 1.96

Substituting the values we have;

5.5+/-1.96(0.2/√80)

5.5+/-1.96(0.022360679774)

5.5+/-0.043826932358

5.5+/-0.044

= ( 5.456, 5.544) ounces

Therefore the 95% confidence interval (a,b) = ( 5.456, 5.544) ounces

could you give more information?

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841