A survey of 900 randomly selected high school students determined that 422 play organized sports. (a) What is the probability that a randomly selected high school student plays organized sports? (b) Interpret this probability.

P = 0.4688 = 46.88%

The probability that a randomly selected high school student plays organized sports is 0.4688.

Step-by-step explanation:

We are given that a survey of 900 randomly selected high school students determined that 422 play organized sports.

(a) What is the probability that a randomly selected high school student plays organized sports?

We know that the probability of an event is given by

P = Number of desired outcomes/total number of outcomes

For the given case, the desired outcomes are those students who play organized sports and the total number of outcomes are 900 randomly selected high school students who were surveyed.

So the probabilty is

P = 422/900

P = 0.4688

P = 46.88%

(b) Interpret this probability

There is a 46.88% chance of randomly selecting a high school student who plays organized sports or in other words, if we randomly choose a high school student then there is a 46.88% probability that the selected student plays organized sports.

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!