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Mathematics, 03.02.2020 18:03 Woodsydal2390

Solve the equation on the interval [0, 2π).

tan2x sin x = tan2x

a. 0, (pi)/2

b. (pi)/2 , 2π

c. (pi)/2 , π

d. 0, π

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Answers: 2

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Solve the equation on the interval [0, 2π).

tan2x sin x = tan2x

a. 0, (pi)/...
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