Solve the equation on the interval [0, 2π).
tan2x sin x = tan2x
a. 0, (pi)/...
Mathematics, 03.02.2020 18:03 Woodsydal2390
Solve the equation on the interval [0, 2π).
tan2x sin x = tan2x
a. 0, (pi)/2
b. (pi)/2 , 2π
c. (pi)/2 , π
d. 0, π
Answers: 2
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