PLS HELP AND ANSWER ASAPPP (i). A line “t” is parallel to 3y = 6x + 9. Find the slope of this line “t”. (ii) Another line “r” is perpendicular to the line 3y = 6x + 9. Find the gradient of the line “r”.

1) 2 (11) - 1/2

Step-by-step explanation:

Given the following:

A line “t” is parallel to 3y = 6x + 9

Equation of a line;

y = mx + c

Where the Coefficient of x, 'm' is the gradient or slope and c is the intercept.

From the equation;

3y = 6x + 9

Divide through by 3

y = 2x + 3

Comparing the line equation with the equation provided :

Coefficient of x = 2, therefore 2 = slope

Since line t is Parallel to y = 2x + 3

Then, slope of line 't' is the same as that of y:

Slope of line 't' = 2

(11) For perpendicular lines :

Slope of original line : 3y = 6x + 9

Divide through by 3

y = 2x + 3

Compare to line equation:

y = mx + c

m = gradient/ slope, c = intercept

Gradient of original line, m = 2

For a line 'r' perpendicular to y = 2x + 3

Gradient, m of line r equals to the negative reciprocal of the gradient of original line

Therefore, gradient of r equals :

-1/2

x^6

step-by-step explanation:

this is correct because:

x-6=0

0*x=0

so

x^6

14

step-by-step explanation:

14