Quadratics helppp plz

x = -3 ± 2√2

Step-by-step explanation:

x² + 6x + 1 = 0

Let's solve by completing the square.

Add -1 and 9 on both sides.

x² + 6x + 9 = 8

Factor left side.

(x + 3)² = 8

Take square root on both sides.

x + 3 = ±√8

Add -3 to both sides.

x = -3 ± 2√2

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?