There are 10 sweets in a bag. 4 are red, 2 are green, 3 are yellow and 1 is purple.
A sweet is chosen at random from the bag.
Here is a probability scale:
А в с
a) Which letter shows the probability of choosing a yellow sweet?
b) Which letter shows the probability of choosing a sweet that is not orange?

Probabilities are used to determine the chances of events.

The probability scale is not given; so, I will give a general explanation.

The given parameters are:

(a) The probability of choosing a yellow sweet

This is calculated using:

So, we have:

Divide 3 by 10

Hence, the probability of choosing a yellow sweet is 0.3

(b) The probability of choosing a sweet that is not orange

This is calculated using:

So, we have:

Divide 0 by 10

Hence, the probability of choosing a sweet that is not orange is 0

Read more about probabilities at:

link

a) 0.3.

b) 1.

Step-by-step explanation:

Note: The scale of probability is not given properly. So, the probability of following events are given below:

It is given that,

Total number of sweets in a bag = 10

Red sweets = 4

Green sweets = 2

Yellow sweets = 3

Purple sweet = 1

a)

We need to find the probability of choosing a yellow sweet.

Therefore, the probability of choosing a yellow sweet is 0.3.

b)

We need to find the probability of choosing a sweet that is not orange.

Therefore, the probability of choosing a sweet that is not orange is 1.

step-by-step explanation:

30% of $420 is 0.30($420) = $126 and $420 + $126 = $546.

or, 130% of $420 is 1.3($420) = $546.

notice that this is not the $600 original list price with which we started.

why doesn't this work?

the method does not work because 30% of $420 is not the same amount as the 30% of $600. it may seem obvious when stated this way, but it is a very common error made on problems of this type. we cannot just use the same percent and get back to the original amount because we are taking that percent of a different value.

to work problems of this type correctly, it is generally best to write an equation for the situation and then solve.

example: since (100% – 30%)(original price) = (sale price)

70% of the   (original price) is $420.

0.7x   = 420

equation image indicator

x = 600

the original cost was $600.

we may also solve this problem using the two-step method. working the problem in two steps requires us to use more algebra skills. we have to know that x = 1x (identity property of multiplicationtext annotation indicator) and that 1x – 0.3x = 0.7x (subtracting like terms). then we solve the problem as follows:

(original price) – 30%(original price) = sale price

x – 0.3x = 420

0.7x = $420

equation image indicator

x = 600

the original cost was $600.  

note that with both of the above methods we do obtain the correct original amount.

example: after a 5% pay raise, hermione is earning $22,680 per year. what was she earning before the pay raise?

105% of (original salary) = current salary

1.05x = 22,680

equation image indicator

x = 21,600

hermione earned $21,600 per year before the pay raise.

this is an example so maybe you will get how to at least do it!

y-y1=4(x-x1)

step-by-step explanation:

this is point-slope form since you only have 4 as the slope it goes in place of m

hope this : )