Touch base for some math nomenclatures. Optimize to 1 to 1 and use all if there are 1 to more connections. 1. An equation for electric current
2. An equation for a linear curve
3. A constant
4. A 1st order differential equation
5. A 2nd order differential equation
6. An ordinary differential equation (1st order)
7. A partial differential equation
8. An integration equation
A. Y = 8x + 6
B. I = V/R
C. y = 8x + 6
D. y' - 8x - 6 = 0
E. 12.23154687854
F. 100 y = (8x + 6)dx
G. dz = 8xdx + 8dy
H. y" = 8

1 - B

2 - A, C

3 - E

4 - D

5 - H

6 - D

7 - None

8 - F, G

Step-by-step explanation:

1. We know the equation that :

Where V is the voltage

I is the Electric Current and

R is the resistance

So,

2. An equation of a linear curve is represented as:

y = mx+c or

Y = mX+C

So, the correct matches are:

A. Y = 8x + 6

and

C. y = 8x + 6

3. A constant:

The constant expression as in options is:

E. 12.23154687854

4. 1st order differential equation is the equation in which there is differentiation done once.

or are used to represent it.

So, correct option is D. y' - 8x - 6 = 0

5. A 2nd order differential equation is the equation in which there is differentiation done once.

or are used to represent it.

So, correct option is H. y" = 8

6. An ordinary differential equation (1st order)

Same as answer to part 4.

or are used to represent it.

So, correct option is D. y' - 8x - 6 = 0

7. A partial differential equation is an equation that contains a term represented as:

but there is no such term given here, so no option matches.

8. An integration equation:

The correct options are F and G.

F.

G.

let x be the money she spent so that she can earn the free t-shirt.

since, she already spent $112.49

⇒

also, as per the statement: jennifer must spend $250 or more in order to qualify for a free t-shirt at the store.

then,

we have an inequality i.,e

subtract 112.49 from both sides we get;

therefore, $137. 51 more money does jennifer need to spend so that she can earn the free t-shirt