Find the area of a triangle whose base is x² + 2x +4 and whose height is 2x²+2x+6. A. 3x⁴ +9x² +10x +12
B. x⁴+ 3x³ + 9x² + 10x + 12
C. 3x⁴+3x³ +9x² +10x+12
D. x⁴+ 9x² + 10x +12

Given the following information, the area of the triangle is x⁴+3x³+9x²+10x+12

Step-by-step explanation:

We must know the formula for finding the area of a triangle in order to begin.

Area = 1/2(b×h)

First we multiply the base and height together.

Base = x² + 2x + 4

Height = 2x² + 2x + 6

(x² + 2x + 4)(2x² + 2x + 6)

Use the foil method to solve this.

2x⁴ + 2x³ + 6x² + 4x³ + 4x² + 12x + 8x² + 8x + 24

Combine like terms.

2x⁴ + 6x³ + 18x² + 20x + 24

Now that we have our product, we have to divide this expression by 2 or 1/2.

(2x⁴ + 6x³ + 18x² + 20x + 24)/2

So, the area of the triangle is x⁴ + 3x³ + 9x² + 10x + 12

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)