A polynomial has been factored below, but some constants are missing.

From the information in the problem, the value of a is 2, the value of b is 2, and the value of c is -6.

Step-by-step explanation:

The first thing we have to do is factor the equation in order to find the value of a, b, and c.

2x³ - 8x² - 24x

Find a common factor that can be easily divisible among all the terms. This common factor is 2x. Factor the equation.

2x(x² - 4x - 12)

Now, we have to factor out the equation in the parentheses. we do this by multiplying the first term by the last term first. Since there is no coefficient number for x², then we assume this number to be 1.

1 × -12 = -12

Now, we have to find two numbers that multiply to get -12 but add together to get -4. These numbers are 2 and -6. Let's plug these numbers into the equation.

2x(x² + 2x - 6x - 12)

Group the first and second terms together and group together the third and last term together in the parentheses.

2x((x² + 2x) + (-6x - 12))

Factor the equation in parentheses.

2x(x + 2)(x - 6)

So, the value of a is 2, the value of b is 2, and the value of c is -6.

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol

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step-by-step explanation: