Assume that the test scores from a college admissions test are normally distributed, with a mean of 450 and a standard deviation of 100. a) What percentage of the people taking the test score between 400 and 500

38.3% of the people taking the test score between 400 and 500

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

What percentage of the people taking the test score between 400 and 500

We have to find the pvalue of Z when X = 500 subtracted by the pvalue of Z when X = 400. So

X = 500

has a pvalue of 0.6915

X = 400

has a pvalue of 0.3085

0.6915 - 0.3085 = 0.383

38.3% of the people taking the test score between 400 and 500

cosine

step-by-step explanation:

8

step-by-step explanation:

just put √(2) * √(32) into a calculator. that will make the answer be 8.