Using the following equation, find the center and radius of the circle. You MUST SHOW ALL WORK and calculations to receive credit. x2 + 4x + y2 − 6y = −4

  the center (h, k) is (-2, 3), and the radius r is 3

Step-by-step explanation:

Separate the x- and y-terms and complete the square for each. The square is completed by adding the square of half the linear term coefficient.

  (x^2 +4x +(4/2)^2) +(y^2 -6y +(-6/2)^2) = -4 +(4/2)^2 +(-6/2)^2

  (x +2)^2 +(y -3)^2 = 9

Compare to the form ...

  (x -h)^2 +(y -k)^2 = r^2

and you see that the center (h, k) is (-2, 3), and the radius r is 3.

17.08

correct me if i am wrong.