I NEED HELP PLEASE, THANKS! :)

  θ = {0, π/2, π, 3π/2, 2π} . . . . choice B

Step-by-step explanation:

In this equation, r will be a maximum where cos(4θ) is a maximum. That is where ...

  4θ = 2kπ . . . . for some integer k

Dividing by 4 gives ...

  θ = k(π/2)

  θ = {0, π/2, π, 3π/2, 2π} . . . . matches choice B

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You will note that the graph also has extremes at odd multiples of π/4. These are the locations where cosine is a minimum and r is negative. It can be argued that r is not a maximum at those points.

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.

c) yes, because of asa or aas