Akite has vertices at (2, 4), (5, 4), (5, 1), and (0, –1).

what is the approximate perimeter of the kite? round to the nearest tenth.

16.7 units

Step-by-step explanation:

We are given that A kite has vertices at (2, 4), (5, 4), (5, 1), and (0, –1).

So, Let A = (2,4)

B =(5,4)

C =(5,1)

D =(0,-1)

So, Find the sides AB ,BC,CD,AC

To find AB use distance formula :

Substitute the values in the formula :

To find BC use distance formula :

Substitute the values in the formula :

To find CD use distance formula :

Substitute the values in the formula :

To find AD use distance formula :

Substitute the values in the formula :

Now perimeter of Kite = Sum of all sides

                                     =AB+BC+CD+AD

                                    =

                                    =

Thus the perimeter of the kite is 16.7 units.

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step-by-step explanation:

answer:   b

step-by-step explanation:

x2 = 16

x can not be a negative number because 16 is positive

the only answer would be positive 8