In a standard game of pool, there are 15 balls labeled 1 through 15. a) In how many ways can the 15 balls be ordered? (5 points) b) In how many ways can 3 of the 15 balls be chosen if order does not matter?

Step-by-step explanation:

If  there are 15 balls labeled 1 through 15 in a standard football game, the order of arrangement of the 15 balls can be done in 15! ways.

15! = 15*14*13*12*11*10*9*8*7*6*5*4*3*2

15! = 1.308*10¹² ways

b)  If 3 of the 15 balls are to be chosen if order does not matter, this can be done in 15C3 number of ways. Since we are selecting some balls out of the total number of balls, we will use the concept of combination.

Using the combination formula nCr = n!/(n-r)!r!

15C3 = 15!/(15-3)!3!

15C3 = 15!/12!3!

15C3 = 15*14*13*12!/12!*6

15C3 = 15*14*13/6

15C3 = 455 ways

lol

step-by-step explanation:

i believe the correct answer is b.