A passenger train can travel 245 miles in the same amount of time it takes a freight train to travel 200 miles. If the raye of the passenger train is 15 MPH faster than the rate of the frieght train find the rate of each Set up a table and solve using an algebraic equation.

Step-by-step explanation:

Let x represent the rate of the freight train. If the rate of the passenger train is 15 MPH faster than the rate of the frieght train, it means that the rate of the passenger train is x + 15

Time = distance/speed

Time that it will take a passenger train to travel 245 miles is

245/(x + 15)

Time that it will take a fright train to travel 200 miles is

200/x

Since both times are the same, it means that

245/(x + 15) = 200/x

Cross multiplying, it becomes

245x = 200(x + 15)

245x = 200x + 3000

245x - 200x = 3000

45x = 3000

x = 3000/45 = 66.67 mph

Rate of freight train is 66.67 mph

Rate of passenger train is 66.67 + 15 = 81.67 mph

x+y = 29, 5x + 2y = 100

step-by-step explanation:

i'm guessing it was a multiple first option was the correct answer

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