A Japanese garden has a circular koi pond in the middle that has a radius of 3 feet. A rectangle with length of 16 feet and width of 14 feet. A circle with radius 3 feet is cut out of the rectangle. What is the area of the Japanese garden around the koi pond? Use 3.14 for Pi. 195.74 feet squared 224.00 feet squared 252.26 feet squared 337.04 feet squared

first, find the area of the circle cut.

r= 3 feet

π=3.14

area of a circle= πr²= 3.14×3×3= 28.26 sq.feet

Now, find the area of the rectangle and subtract it by the area of the circle.

area of rectangle = l×b

length of the rectangle= 16 feet

breadth/width of the rectangular garden= 14 feet

area=  16×14= 224 sq. feet

now, area of the garden surrounding the koi pond=  224-28.26

                                                                                     =195.74 sq. feet

1.4

2.3

step-by-step explanation:

the formula for the constant of variation is

y= kx

divide each side by x

y/x =kx/x

y/x =k

we know a and y

1.   y/x = k

4/1 =4

check the other values to make sure they are the same

8/2 = 4   12/3 =4   and 16/4 =4  

the constant of variation is 4

2.   y/x = k

3/1 =3

check the other values to make sure they are the same

6/2 = 3   9/3 =3   and 12/4 =3  

the constant of variation is 3

i believe that the slope of the line is -5

step-by-step explanation: