Find the equation of a line perpendicular to 4x+2y=3 that contains the point (1,5)

  x -2y = -9

Step-by-step explanation:

We can start by swapping the coefficients of x and y, then negating one of them. We can finish by evaluating the expression at the given point to find the constant.

  2x -4y = constant

  2(1) -4(5) = -18 = constant

So, an equation could be ...

  2x -4y = -18

We notice that all of the coefficients of this equation are divisible by 2, so we can remove a factor of 2 from the equation:

  x -2y = -9

c.

step-by-step explanation:

substitution for (0,1)

y=x^2+4x+1

1=0^2+4(x)0+1

1=0+4(x)0+1

1=4(x)0+1

1=0+1

1=1

substitution for (-3,-2)

y=x+1

-2=-3+1

-2=-2

step-by-step explanation:

assume that you have 3 different side lengths.   apply the pythagorean theorem here:   square each of the two shortest sides; call them a and b, so that their squares are a² and b².   also square the longest side, calling the result c².

now, if a² + b² = c² is true, the triangle is a right triangle; otherwise it is not a right triangle.