Find the smallest number which gives remainders 1, 2, 3, 4, and 5 when divided respectively by 2, 3, 4, 5, and 6.

step-by-step explanation:

20% of 120 is 24. if you subtract 24 from 120 you get 96

false

step-by-step explanation:

4y - 6 + 4y^2 - 9

before simplifying this contains 4 terms

after simplifying

4y -15 + 4y^2

it contains 3 terms

55/i dont know i do it for the points

step-by-step explanation:

whats the