Two positive intergers have a product of 50 one interger is twice the other . what are the intergers

10 and 5.

Step-by-step explanation:

Let the integers be x and y.

xy = 50

x = 2y

Put x as 2y in the first equation.

(2y)y = 50

2y² = 50

y² = 50/2

y² = 25

y = √25

y = 5

Put y as 5 in the second equation.

x = 2(5)

x = 10

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5