Which is the equation of a parabola with a directrix at y = 2 and a focus at (5, 0). y = one fourth(x − 5)2 + 1 y = one fourth(x + 1)2 − 5 y = −one fourth(x + 1)2 − 5 y = −one fourth(x − 5)2 + 1

answer

see attachment

explanation

the given function is

this function has y-intercept at

-4 and a slope of 2.

note that, the graph has a positive slope.

the graph that represents this function is the straight line that moves upward from left to right.

the graph touches the y-axis at -4.

the correct choice is the graph shown in the attachment.

10 b/c 5*2 =10

step-by-step explanation:

i think the answer is true

step-by-step explanation:

im not sure of the names, but the answer is 48