Find a missing numerators in each of the following problems. a. 10/15 = /60 b. /180 = 4 / 9 c. 7/11 = /121 d. /144 = 2/6

  a) 40

  b) 80

  c) 77

  d) 48

Step-by-step explanation:

To find the missing numerator, multiply the equation by the denominator of the fraction with the missing numerator.

a) (10/15)(60) = (x/60)(60)

  40 = x

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b) (x/180)(180) = (4/9)(180)

  x = 80

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c) (7/11)(121) = (x/121)(121)

  77 = x

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d) (x/144)(144) = (2/6)(144)

  x = 48

"standard form:

3x2 + 14x − 10 = 0

solutions based on quadratic formula:

x1   = −14 − √ 142 − 4×3×(−10) /   2×3   = −14 − 2 × √ 79 /   6   ≈ −5.296

x2   = −14 + √ 142 − 4×3×(−10) /   2×3   = −14 + 2 × √ 79 /   6   ≈ 0.629