Find the perimeter of the following shape, rounded to the nearest tenth: Shape ABCD is shown. Point A is at negative 3, 5. Point B is at 2, 6. Point C is at 0, 2. Point D is at negative 5, 1.

19.04

Step-by-step explanation:

find the length of AB,BC,CD , and AD

distance=√(x2-x1)^2+(y2-y1)^2

A(-3,5), B(2,6),C(0,2),D(-5,1)

line AB :d=√(2−(−3))^2+(6−6)^2

AB=5

BC=d=√(0−2)^2+(2−6)^2=√20=2√5

CD:√26

DA:√20

perimeter=AB+BC+CD+DA=5+√20+√20+√26=19.04

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the answer is 62.8 cubic units