Show all work to solve 3x^2-5x-2=0

The roots are {2, -1/3}

Step-by-step explanation:

The coefficients of this quadratic function are a = 3, b = -5 and c = -2.

Let's use the quadratic formula to find the roots of the given 3x^2-5x-2=0.

The discriminant is b^2 - 4(a)(c), or (-5)^2 - 4(3)(-2), or 25 + 24 = 49.

Thus, the roots are:

      -(-5)±√49        5 ± 7

x = = = 2 and -1/3

          2(3)                  6

9.55 degrees.

step-by-step explanation:

the given angle is

1 cycle is equal to 2π radians. so 4π will be equal to two cycles.

5.166667π-4π = 1.166667π

hence, this angle goes a little more than negative x axis.

1.166667π-π= 0.166667π

hence, the reference angle is 0.166667π radians.

1 radian = 57.2958 degrees

now, in degrees, this should be equals to 9.55 degrees.

the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents