What is the equation of a line that goes through the point (0, 2) and has a slope of 1?

y=x+2

Step-by-step explanation:

The slope-intercept equation is y=mx+b. The m is slope, and the b is the y-intercept. Since we are given the slope, we can fill it into m. We also know  that the y-intercept is on the y-axis, meaning the x-coordinate is 0. The point we were given is (0,2). This means the y-intercept is 2. Our equation is y=x+2.

y=x+2

Step-by-step explanation:

Slope intercept form is:

y=mx+b

where m is the slope and b is the y-intercept.

We know that this line has a slope of 1. Therefore, we can substitute 1 in for m.

y=1x+b

1x is equal to just x, so change 1x to x.

y=x+b

Now we must find the y-intercept, or b.

Y-intercepts are where the line crosses the y axis. The x-coordinate is always a 0.

Therefore, (0,y) is the coordinates of a y-intercept, and the "y" is the y-intercept.

We are given the point:

(0,2)

Since the x-coordinate is a 0, the y-intercept is 2. Substitute 2 in for b.

y=x+b

y=x+2

The equation of the line is y=x+2

idk what the answer is but for the points

step-by-step explanation:

the first one and the second one that's the answer

is this part of a question or something