Determine whether the point (–3,–6) is in the solution set of the system of inequalities below. x ≤ –3 y < 5∕3x + 2

The point (–3,–6) is not  in the solution set of the system of inequalities below.

x ≤ –3 y < 5∕3x + 2

Step-by-step explanation:

Given point (-3, -6)

inequality

x ≤ –3

It means that value of x should be less than or equal to -3

since in point (-3,-6) , -3 is point for representing x which is equal to -3 and hence satisfy the criteria for valid value of x,

thus, -3 lie in the solution set of inequality x ≤ –3

lets now see for y = -6

to do that we will put x = -3 in the given below inequality

y < 5∕3x + 2

y < 5∕3*-6 + 2

y < -10 + 2

y < - 8

Thus, inequality suggests that value of y should be less than -8.

but here y is -6, if we see number line -6 is greater than -8 and hence does not belong to the solution set  y < 5∕3x + 2 when x = -3

Thus, the point (–3,–6) is not  in the solution set of the system of inequalities below. x ≤ –3 y < 5∕3x + 2

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)