H(x)=1/8x^3-x^2 What is the average rate of change of h over the interval -2≤x≤2?

Step-by-step explanation:

The average rate of change of h(x) in the closed interval [ a, b ] is

Here [ a , b ] = (- 2, 2 ] , thus

h(b) = h(2) = (2)³ - 2² = 1 - 4 = - 3

h(a) = h(- 2) = (- 2)³ - (- 2)² = - 1 - 4 = - 5 , thus

average rate of change = = =

the inequality is:

250c+180g≥950

step-by-step explanation:

let c denotes the number of days in a week   miyoko worked as a cryptographer.

and g denotes the number of days in a week she works as a geologist.

now we are given that she earns $250 for every day she works as a cryptographer,and earns $180 for every day she works as a geologist.

now miyoko's goal is to earn more than $950 this week.

hence, the inequality could be represented as:

250c+180g≥950

94

step-by-step explanation:

average the numbers and use a variable to figure out the minimum to get a 90.

(79+94+91+92+x)/5=90

x = 94