I NEED HELP PLEASE, THANKS! :) Anne is pushing a wheelbarrow filled with mulch to place in her garden. She is pushing the wheelbarrow with a force of 70 N at an angle of 50° with the horizontal. How much work in joules is Anne doing when she pushes the wheelbarrow 25 meters? (Show work)

Hey there! :)

1124.8 J.

Step-by-step explanation:

Given:

Distance: 25 meters.

Force: 70 N.

Direction: 50° with the horizontal.

Start by calculating the magnitude of the vector:

cos (50) = |x| / 70

70 · cos (50) = |x|

Solve:

44.99 ≈ |x|

This is the magnitude. To calculate the amount of work done, simply multiply by the distance she pushed the wheelbarrow:

44.99 × 25 ≈ 1124.8 J.

Now we have to find,

the work in joules is Anne doing when she pushes the wheelbarrow 25 meters.

It is given that,

→ Distance = 25 m

→ Force = 70 N

→ Direction = 50° with the horizontal

Then calculate the vector magnitude,

→ cos (50) = x/70

→ x = 70 × cos (50)

→ x = 44.9951326783

→ x = 44.99

Now the magnitude is 44.99.

Then multiply the magnitude by the distance to find the work done,

→ 44.99 x 25

→ 1124.75

→ 1124.8 J

Hence, 1124.8 J is work done by Anne.

she will sew have sewn five dresses   and be 1/3 done with the sixth one in an hour.

step-by-step explanation:

3/4 of an hour=45 mins

lucy makes 1 dress per 11.25 minutes

45 mins+11.25 mins=56.25 mins

60 mins- 56.25 mins=3.75 mins

3.75 mins is 1/3 of of 11.25 mins

therefore she the other 1/3 would be part of the hour and she will have sewn 5 dresses and begun the sixth.

contact me if you have any questions you are welcome.