In parallelogram ABCD, m∠ABD = 83°, m∠BDA = 34°, and m∠BCD = °.

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63°

Step-by-step explanation:

We are told in the above question that for parallelogram ABCD, ∠ABD=83° and ∠BDA=34°.

To get the above angles, parallelogram ABCD was split into two triangles by a diagonal given us ∆ABD and ∆BCD

Remember that angles in a triangle = 180°

∆ABD has ∠ABD=83°, ∠BDA=34° and ∠DAB

180° = ∠ABD + ∠BDA+ ∠DAB

180° = 83° + 34° + ∠DAB

∠DAB = 180°-117°

=63°

Since ∆ABD and ∆BCD are similar triangles because they are from one parallelogram,

∠DAB = ∠BCD

= 63°

Therefore, the measure of the angle BCD is 63°.

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answer: the first graph

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