Can someone help me solve (a) and (c) pls.
Thanks

Area of ABCD = 959.93 units²

Step-by-step explanation:

a). By applying Sine rule in the ΔABD,

 Sin∠DBA =

 m∠DBA =

 m∠DBA = 45.64°

 Therefore, m∠ADB = 180° - (110° + 45.64°) = 24.36°

                  m∠ADB = 24.36°

c). Area of ABCD = Area of ΔABD + Area of ΔBCD

  Area of ΔABD = AD×BD×Sin()

                           = 35×46Sin(12.18)

                           = 339.68 units²

   Area of ΔBCD = BD×BC×Sin()°

                            = 46×27×(0.4994)

                            = 620.25 units²

   Area of ABCD = 339.68 + 620.25

                            = 959.93 units²

36 is the final answer! : )

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b