In the given figure angle 1 is equal to angle 2 then the measurements of angle 3 and angle 4 are

The measurements of angle 3 and angle 4 are 119degrees and 119degrees respectively.

The sum of the interior angle of the triangle is 180degrees.

According to the diagram shown:

m<1 + m<2 + 58 = 180

Since <1 = <2, hencce:

m<1 + m<1 + 58 = 180

2m<1 = 180 - 58

2m<1 = 122

m<1 = 122/2

m<1 = 61 degrees

Since <1 = <2, thereofore m<3 = m<4

Get the measure of m<3

m<1 + m<3 = 180 (supplementary angles)

61 + m<3 = 180

m<3 = 180 - 61

m<3 = 119 degrees

Recall that m<3 = m<4, hence m<4 = 119degrees

The measurements of angle 3 and angle 4 are 119degrees and 119degrees respectively.

Learn more here: link

(3) =  119

(4) =  119

Step-by-step explanation:

Given isosceles triangle with vertex angle 58.

Need exterior angles of base angles 1 & 2.

Solution:

Vertex angle = 58.

Base angle = x

Sum of triangles = 180 =>

x + x + 58 = 180

Solve for x

x = (180-58)/2 = 122/2 = 61

Exterior angles are supplementary to interior (base) angles, so

(3) = 180-(1) = 180 - 61 = 119

(4) = 180-(2) = 180 - 61 = 119

* note: supplementary means sum of two angles = 180.