The points (0, –1) and (4, 5) lie on the straight line L. Find an equation of the line which is parallel to L and passes through the point (–2, 0).

y = 3/2x + 3.

Step-by-step explanation:

With these two points, we can find the equation of line L.

y = mx + b

Slope: (5 --1) / (4 - 0) = 5 + 1 / 4 = 6 // 4 = 3/2

Intercept: [stated by the first pair of coordinates] (0, -1)

y = 3/2x - 1

Since the line is parallel to L, the slope is the same as line L.

y = 3/2x + b

The line passes through (-2, 0), so we can substitute the points into the equation and solve for b.

0 = 3/2 * -2 + b

b - 3 = 0

b = 3

So, the equation of the line which is parallel to L and passes through the point (-2, 0), is y = 3/2x + 3.

Hope this helps!