Which complex number from the table multiplied with B from the table will result in the product 159 + 27i? A -3 − 4i
B -7 − 6i
C 13 + i
D -9 + 6i
E 8 − 8i
F -15 + 9i
G 2 + 12i
H 6 − 10i

F. -15 + 9i

Step-by-step explanation:

B = (-7 -6i)

Multiply B by F = (-15 + 9i), would give;

B × F = (-7 -6i) × (-15 + 9i)

        = -7 (-15 + 9i) - 6i (-15 + 9i)

       = 105 -63i + 90i - 54()

But = -1, so that:

105 -63i + 90i -54() = 105 -63i + 90i -54(-1)

                                  = = 105 -63i + 90i + 54

          = 159 + 27i

B × F = 159 + 27i

Thus the required complex number is F (-15 + 9i).

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph